0=16x^2+36x+4

Solution for 0=16x^2+36x+4 equation:

0=16x^2+36x+4

We move all terms to the left:

0-(16x^2+36x+4)=0

We add all the numbers together, and all the variables

-(16x^2+36x+4)=0

We get rid of parentheses

-16x^2-36x-4=0

a = -16; b = -36; c = -4;
Δ = b2-4ac
Δ = -362-4·(-16)·(-4)
Δ = 1040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1040}=\sqrt{16*65}=\sqrt{16}*\sqrt{65}=4\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{65}}{2*-16}=\frac{36-4\sqrt{65}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{65}}{2*-16}=\frac{36+4\sqrt{65}}{-32}
$